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Simplifying c2 + -2c + -120 = 0 Reorder the terms: -120 + -2c + c2 = 0 Solving -120 + -2c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (-10 + -1c)(12 + -1c) = 0Subproblem 1
Set the factor '(-10 + -1c)' equal to zero and attempt to solve: Simplifying -10 + -1c = 0 Solving -10 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1c = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1c = 0 + 10 -1c = 0 + 10 Combine like terms: 0 + 10 = 10 -1c = 10 Divide each side by '-1'. c = -10 Simplifying c = -10Subproblem 2
Set the factor '(12 + -1c)' equal to zero and attempt to solve: Simplifying 12 + -1c = 0 Solving 12 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1c = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1c = 0 + -12 -1c = 0 + -12 Combine like terms: 0 + -12 = -12 -1c = -12 Divide each side by '-1'. c = 12 Simplifying c = 12Solution
c = {-10, 12}
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